sederhanakan bentuk berikut:a. 2 log 64 - 2 log 16 b. 4 log 16

4 log 16For example, in the problem given, by rewriting 16 as a power of 4, we made it easier to solve the equation. Once the bases match, equate the exponents and solve it like a regular algebra14 Explanation: Remember that displaystyle{16}={2}^{{4}} : displaystyle{{log}_{{16}}{left({2}rht)}}={{log}_{{16}}{left({16}^{{frac{{1}}{{4}}}}rht)}}=frac{{1}}{{4}}